The Journal of the Indian Mathematical Society

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On Equations for determining cosπ/ (2n+1)


     

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Taking the equation cos2nθ + cosθ = 0, we have cos 2nθ=cos(π-θ), So that 2nθ=(2r*#177;1)π±θ.
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  • On Equations for determining cosπ/ (2n+1)

Abstract Views: 193  |  PDF Views: 0

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Taking the equation cos2nθ + cosθ = 0, we have cos 2nθ=cos(π-θ), So that 2nθ=(2r*#177;1)π±θ.