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On the Relative Extrema of the Hermite Orthogonal Functions
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1. The Hermite polynomials Hn (x) satisfy the recurrence relation
Hn+1 (x)=2xHn(x)-2nHn-1(x), n≥I, (I.I)
H0(x) = I, H1(x) = 2x, H2(x) = 4x2-2, H3(x) = 8x3-12x. (I.2)
We follow the notation of G. Szego [3, pp. 101-102]. We have
z"+(2n+1-x2) z = 0, Z = e-x2/2 Hn(x) = zn(x), (I.3).
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