The Journal of the Indian Mathematical Society

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Problem of Krull-Schmidt-Remak-Azumaya-Matlis


     

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He also observed that in case B is noetherian, the answer is in the affirmative. In [2], Faith and Walker have shown that the answer is in the affirmative in case M is injective. As shown by Jean-Yves Chamard [1], the answer is again in the affirmative if M satisfied the condition: the intersection of two complemented submodules of M is again a complemented submodule of M.
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  • Problem of Krull-Schmidt-Remak-Azumaya-Matlis

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He also observed that in case B is noetherian, the answer is in the affirmative. In [2], Faith and Walker have shown that the answer is in the affirmative in case M is injective. As shown by Jean-Yves Chamard [1], the answer is again in the affirmative if M satisfied the condition: the intersection of two complemented submodules of M is again a complemented submodule of M.