The Journal of the Indian Mathematical Society

Open Access Open Access  Restricted Access Subscription Access
Open Access Open Access Open Access  Restricted Access Restricted Access Subscription Access

Problem of Krull-Schmidt-Remak-Azumaya-Matlis


     

   Subscribe/Renew Journal


He also observed that in case B is noetherian, the answer is in the affirmative. In [2], Faith and Walker have shown that the answer is in the affirmative in case M is injective. As shown by Jean-Yves Chamard [1], the answer is again in the affirmative if M satisfied the condition: the intersection of two complemented submodules of M is again a complemented submodule of M.
Subscription Login to verify subscription
User
Notifications
Font Size


Abstract Views: 230

PDF Views: 0




  • Problem of Krull-Schmidt-Remak-Azumaya-Matlis

Abstract Views: 230  |  PDF Views: 0

Authors

Abstract


He also observed that in case B is noetherian, the answer is in the affirmative. In [2], Faith and Walker have shown that the answer is in the affirmative in case M is injective. As shown by Jean-Yves Chamard [1], the answer is again in the affirmative if M satisfied the condition: the intersection of two complemented submodules of M is again a complemented submodule of M.